GRBLinExpr#

class GRBLinExpr#

Gurobi linear expression object. A linear expression consists of a constant term, plus a list of coefficient-variable pairs that capture the linear terms. Linear expressions are used to build constraints. They are temporary objects that typically have short lifespans.

The GRBLinExpr class is a sub-class of the abstract base class GRBExpr.

You generally build linear expressions using overloaded operators. For example, if x is a GRBVar object, then x + 1 is a GRBLinExpr object. Expressions can be built from constants (e.g., expr = 0), variables (e.g., expr = 1 * x + 2 * y), or from other expressions (e.g., expr2 = 2 * expr1 + x, or expr3 = expr1 + 2 * expr2). You can also modify existing expressions (e.g., expr += x, or expr2 -= expr1).

Another option for building expressions is to use the addTerms method, which adds an array of new terms at once. Terms can also be removed from an expression, using remove.

Note that the cost of building expressions depends heavily on the approach you use. While you can generally ignore this issue when building small expressions, you should be aware of a few efficiency issues when building large expressions:

  • You should avoid using expr = expr + x in a loop. It will lead to runtimes that are quadratic in the number of terms in the expression.

  • Using expr += x (or expr -= x) is much more efficient than expr = expr + x. Building a large expression by looping over += statements is reasonably efficient, but it isn’t the most efficient approach.

  • The most efficient way to build a large expression is to make a single call to addTerms.

To add a linear constraint to your model, you generally build one or two linear expression objects (expr1 and expr2) and then use an overloaded comparison operator to build an argument for GRBModel::addConstr. To give a few examples:

model.addConstr(expr1 <= expr2)
model.addConstr(expr1 == 1)
model.addConstr(2*x + 3*y <= 4)

Once you add a constraint to your model, subsequent changes to the expression object you used to build the constraint will not change the constraint (you would use GRBModel::chgCoeff for that).

Individual terms in a linear expression can be queried using the getVar, getCoeff, and getConstant methods. You can query the number of terms in the expression using the size method.

Note that a linear expression may contain multiple terms that involve the same variable. These duplicate terms are merged when creating a constraint from an expression, but they may be visible when inspecting individual terms in the expression (e.g., when using getVar).

GRBLinExpr GRBLinExpr(double constant = 0.0)#

Linear expression constructor that creates a constant linear expression.

Parameters:

constant – (optional) Constant value for expression.

Returns:

A constant expression object.

GRBLinExpr GRBLinExpr(GRBVar var, double coeff = 1.0)#

Linear expression constructor that creates an expression with one term.

Parameters:

  • var – Variable for expression term.

  • coeff – (optional) Coefficient for expression term.

Returns:

An expression object containing one linear term.

void addTerms(const double *coeffs, const GRBVar *vars, int count)#

Add new terms into a linear expression.

Parameters:

  • coeffs – Coefficients for new terms.

  • vars – Variables for new terms.

  • count – Number of terms to add to the expression.

void clear()#

Set a linear expression to 0.

You should use the overloaded expr = 0 instead. The clear method is mainly included for consistency with our interfaces to non-overloaded languages.

double getConstant()#

Retrieve the constant term from a linear expression.

Returns:

Constant from expression.

double getCoeff(int i)#

Retrieve the coefficient from a single term of the expression.

Parameters:

i – Index for coefficient of interest.

Returns:

Coefficient for the term at index i in the expression.

double getValue()#

Compute the value of a linear expression for the current solution.

Returns:

Value of the expression for the current solution.

GRBVar getVar(int i)#

Retrieve the variable object from a single term of the expression.

Parameters:

i – Index for term of interest.

Returns:

Variable for the term at index i in the expression.

GRBLinExpr operator=(const GRBLinExpr &rhs)#

Set an expression equal to another expression.

Parameters:

rhs – Source expression.

Returns:

New expression object.

GRBLinExpr operator+(const GRBLinExpr &rhs)#

Add one expression into another, producing a result expression.

Parameters:

rhs – Expression to add.

Returns:

Expression object which is equal the sum of the invoking expression and the argument expression.

GRBLinExpr operator-(const GRBLinExpr &rhs)#

Subtract one expression from another, producing a result expression.

Parameters:

rhs – Expression to subtract.

Returns:

Expression object which is equal the invoking expression minus the argument expression.

void operator+=(const GRBLinExpr &expr)#

Add an expression into the invoking expression.

Parameters:

expr – Expression to add.

void operator-=(const GRBLinExpr &expr)#

Subtract an expression from the invoking expression.

Parameters:

expr – Expression to subtract.

void operator*=(double multiplier)#

Multiply the invoking expression by a constant.

Parameters:

multiplier – Constant multiplier.

void remove(int i)#

Remove the term stored at index i of the expression.

Parameters:

i – The index of the term to be removed.

boolean remove(GRBVar var)#

Remove all terms associated with variable var from the expression.

Parameters:

var – The variable whose term should be removed.

Returns:

Returns true if the variable appeared in the linear expression (and was removed).

unsigned int size()#

Retrieve the number of terms in the linear expression (not including the constant).

Returns:

Number of terms in the expression.